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JEE Main 10 Apr 2019 Paper 1 Solved Paper

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Question : 19

Total: 90

A uniformly charged ring of radius 3a and total charge q is placed in xy-plane centred at orign. A point charge q is moving towards the ring along the z-axis and has speed vatz=4a The minimum value of v such that it crosses the origin is:

√
2
m
(
2
15
q2
4π∊0a
)
1
2
√
2
m
(
1
15
q2
4π∊0a
)
1
2
√
2
m
(
1
5
q2
4π∊0a
)
1
2
√
2
m
(
4
15
q2
4π∊0a
)
1
2

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