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JEE Main 10 April 2015 Paper
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© examsnet.com
Question : 3
Total: 90
A block of mass
m
=
10
kg rests on a horizontal table. The coefficient of friction between the block and the table is
0.05
. When hit by a bullet of mass
50
g moving with speed
υ
, that gets embedded in it, the block moves and comes to stop after moving a distance of 2 m on the table. If a freely falling object were to acquire speed
υ
10
after being dropped from height H then neglecting energy losses andtaking
g
=
10
m
s
−
2
,the value of H is close to :
0.2 km
0.3 km
0.4 km
0.5 km
None of the above
Validate
Solution:
Momentum conservation
0.05
V
=
10
V
0
0
−
V
0
2
=
2
(
−
µ
g
)
2
V
0
=
√
2
object falling from height H.
V
10
=
√
2
g
H
H
=
40
m
=
0.04
km
© examsnet.com
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