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JEE Main 10 April 2016 Paper
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© examsnet.com
Question : 5
Total: 90
In the figure shown ABC is a uniform wire.If centre of mass of wire lies vertically below point A, then
B
C
A
B
is close to :
1.85
1.37
1.5
3
Validate
Solution:
If CM lies vertically below A ⇒ as per choose coordinate axis in x-coordinate is equal to
l
1
2
X
cm
=
m
x
1
+
m
x
2
m
1
+
m
2
l
1
2
=
(
λ
l
1
)
(
l
1
4
)
+
(
λ
l
2
)
(
l
2
2
)
λ
(
l
1
+
l
2
)
l
1
2
2
+
l
1
l
2
2
=
l
1
2
4
+
l
2
2
2
l
1
2
4
+
l
1
l
2
2
−
l
2
2
2
=
0
l
1
2
+
2
l
1
l
2
−
2
l
2
2
=
0
l
1
=
−
2
l
2
±
√
4
l
1
2
+
4.1
(
+
2
l
2
2
)
2
l
1
=
−
2
l
2
+
√
12
l
2
2
2
l
1
=
−
2
l
2
+
2
√
3
l
2
2
l
1
=
(
√
3
−
1
)
l
2
l
2
l
1
=
1
√
3
−
1
×
√
3
+
1
√
3
+
1
l
2
l
1
=
√
3
+
1
2
=
2.732
2
=
1.366
≃
1.37
© examsnet.com
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