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JEE Main 10 Jan 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 6
Total: 90
In a Young's double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle
1
40
rad by using light of wavelength
λ
1
. When the light of wavelength
λ
2
is used a bright fringe is seen at the same angle in the same set up.Given that
λ
1
and
λ
2
are in visible range (380 nm to 740 nm), their values are :
380 nm, 500 nm
625 nm, 500 nm
380 nm, 525 nm
400 nm, 500 nm
Validate
Solution:
Path difference = d sinθ ~ dθ
= 0.1 ×
1
40
mm = 2500 nm
or bright fringe, path difference must beintegral multiple of λ
∴ 2500 =
n
λ
1
=
m
λ
2
∴
λ
1
= 625 ,
λ
2
= 500 (from m = 5)
(for n = 4)
© examsnet.com
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