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JEE Main 10 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 18
Total: 90
A metal plate of area 1 ×
10
–
4
m
2
is illuminated by a radiation of intensity 16 mW/
m
2
.The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electronsper second and their maximum energy, respectively, will be : [1 eV = 1.6 ×
10
–
19
J]
10
10
and 5 eV
10
14
and 10 eV
10
12
and 5 eV
10
11
and 5 eV
Validate
Solution:
I =
n
E
A
t
16 ×
10
−
3
=
(
n
t
)
photon
10
×
1.6
×
10
−
19
10
−
4
=
10
12
© examsnet.com
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