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JEE Main 10 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 30
Total: 90
Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is :
152
15
M
R
2
17
15
M
R
2
137
15
M
R
2
209
15
M
R
2
Validate
Solution:
For Ball
using parallel axis theorem
I
ball
=
2
5
M
R
2
+
M
(
2
R
)
2
=
22
5
M
R
2
2 balls or
44
5
M
R
2
Irod = for rod
M
(
2
R
)
2
R
=
M
R
2
3
I
system
=
I
ball
+
I
rod
=
44
5
M
R
2
+
M
R
2
3
=
137
15
M
R
2
© examsnet.com
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