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JEE Main 10 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 45
Total: 90
If
25
Σ
r
=
0
{
50
C
r
.
50
−
r
C
25
−
r
} = K
(
50
C
25
)
, then K is equal to :
2
25
- 1
(
25
)
2
2
25
2
24
Validate
Solution:
25
Σ
r
=
0
{
50
C
r
.
50
−
r
C
25
−
r
}
=
25
Σ
r
=
0
50
!
r
!
(
50
−
r
)
!
×
(
50
−
r
)
!
(
25
)
!
(
25
−
r
)
!
=
25
Σ
r
=
0
50
!
25
!
25
!
×
(
25
)
!
(
r
)
!
(
25
−
r
)
!
=
50
C
25
25
Σ
r
=
0
25
C
r
=
(
2
25
)
50
C
25
∴ K =
2
25
© examsnet.com
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