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JEE Main 11 April 2015 Paper
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© examsnet.com
Question : 21
Total: 90
A short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East - West line, drawn through the middle point of the magnet.The magnetic moment of the magnet in
A
m
2
is close to
(Given
µ
0
4
π
=
10
−
7
) in SI units and
B
H
=
Horizontal component of earth's magnetic field
=
3.6
×
10
−
5
Tesla)
9.7
4.9
19.4
14.6
Validate
Solution:
µ
0
4
π
M
r
3
=
3.6
×
10
−
5
M
=
3.6
×
10
−
5
10
−
7
(
0.3
)
3
M
=
9.7
A
m
2
© examsnet.com
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