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JEE Main 11 April 2015 Paper
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© examsnet.com
Question : 3
Total: 90
A large number (n) of identical beads,each of mass m and radius r are strung on a thin smooth rigid horizontal rod of length L (L > > r) and are rest at random positions.The rod is mounted between two rigid supports (see figure).If one of the beads is now given a speed v, the average force experienced by each support after a long time is (assume all collision are elastic):
m
v
2
L
−
n
r
m
v
2
L
−
2
n
r
m
v
2
2
(
L
−
n
r
)
zero
Validate
Solution:
Space between the supports for motion of beads is
L
–
2
n
r
F
=
2
m
V
2
(
L
−
2
n
r
)
V
=
m
V
2
L
−
2
n
r
© examsnet.com
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