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JEE Main 11 April 2015 Paper
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© examsnet.com
Question : 8
Total: 90
A cylindrical block of wood (density
=
650
k
g
m
−
3
), of base area
30
c
m
2
and height 54 cm, floats in a liquid of density
900
k
g
m
−
3
.The block is depressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :
65 cm
52 cm
39 cm
26 cm
Validate
Solution:
m
g
=
F
s
h = Length of block immerged in water
650
×
A
×
54
×
10
−
2
g
=
900
×
A
×
h
g
h
=
0.39
m
=
39
c
m
© examsnet.com
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