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JEE Main 11 Jan 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 28
Total: 90
An object is at a distacen of 20 m from a convex lens of focal length 0.3 m. The lens forms an image of the object. If the object moves away from the lens at a speed of 5 m/s, the speed and direction of the image will be :
0.92 ×
10
–
3
m/s away from the lens
2.26 ×
10
–
3
m/s away from the lens
1.16 ×
10
–
3
m/s towards the lens
3.22 ×
10
–
3
m/s towards the lens
Validate
Solution:
From lens equation
1
v
−
1
u
=
1
f
1
v
−
1
(
−
20
)
=
1
(
0.3
)
=
10
3
1
v
=
10
3
−
1
20
1
v
=
197
60
; v =
60
197
m =
(
v
u
)
=
(
60
197
)
20
velocity of image wrt. to lens is given by
v
I
∕
L
=
m
2
v
O
∕
L
direction of velocity of image is same as that of object
v
O
∕
L
= 5 m/s
v
I
∕
L
=
(
60
×
1
197
×
20
)
2
(5)
= 1.16 ×
10
−
3
m/s towards the lens
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