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JEE Main 11 Jan 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 32
Total: 90
The area (in sq. units) of the region boundedby the curve
x
2
= 4y and the straight linex = 4y – 2 :-
5
4
9
8
3
4
7
8
Validate
Solution:
x = 4y – 2 &
x
2
= 4y
⇒
x
2
= x + 2 ⇒
x
2
– x – 2 = 0
x = 2, – 1
So ,
2
∫
−
1
(
x
+
2
4
−
x
2
4
)
dx =
9
8
© examsnet.com
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