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JEE Main 11 Jan 2019 Shift 1 Solved Paper
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© examsnet.com
Question : 4
Total: 90
A liquid of density ρ is coming out of a hose pipe of radius a with horizontal speed v and hits a mesh. 50% of the liquid passes through the mesh unaffected. 25% looses all of its momentum and 25% comes back with the same speed. The resultant pressureon the mesh will be :
ρ
v
2
3
4
ρ
v
2
1
2
ρ
v
2
1
4
ρ
v
2
Validate
Solution:
Momentum per second carried by liquid persecond is
ρ
a
v
2
net force due to reflected liquid = 2 ×
[
1
4
ρ
a
v
2
]
net force due to stopped liquid =
1
4
ρ
v
2
Total force =
3
4
ρ
v
2
net pressure =
3
4
ρ
v
2
© examsnet.com
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