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JEE Main 11 Jan 2019 Shift 2 Solved Paper
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© examsnet.com
Question : 29
Total: 90
A copper wire is wound on a wooden frame, whose shape is that of an equilateral triangle. If the linear dimension of each side of the frame is increased by a factor of 3, keeping the number of turns of the coil per unit length of the frame the same, then the self inductance of the coil :
Decreases by a factor of 9
√
3
Increases by a factor of 3
Decreases by a factor of 9
Increases by a factor of 27
Validate
Solution:
Total length L will remain constant
L = (3a) N , (N = total turns)
and length of winding = (d) N
(d = diameter of wire)
self inductance =
µ
0
n
2
Al
=
µ
0
n
2
(
√
3
a
2
4
)
dN
α
a
2
N α a
So self inductance will become 3 times
© examsnet.com
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