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JEE Main 12 Apr 2019 Paper 1 Solved Paper

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Question : 29

Total: 90

When M1 gram of ice at −10°C (specific heat = 0.5 cal g−1 °C−1 is added to M2 is added to of water at 50°C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in calg−1 is:

5 M1
M1
−50
5 M2
M1
5 M2
M1
−5
50 M2
M1
−5

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