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JEE Main 12 Apr 2019 Paper 1 Solved Paper

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Question : 4

Total: 90

An excited He+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength λ , energy E=

.

n = 4
N = 5
N = 7
N = 6

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