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JEE Main 15 Apr 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 8
Total: 90
Take the mean distance of the moon and the sun from the earth to be
0.4
×
10
6
km and
150
×
10
6
k
m
respectively. Their masses are
8
×
10
22
k
g
and
2
×
10
30
kg respectively. The radius of the earth is 6400 km. Let
∆
F
1
be the difference in the forces exerted by the moon at the nearest and farthest points on the earth and
∆
F
2
be the difference in the force exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to
∆
F
1
∆
F
2
2
10
−
2
0.6
6
Validate
Solution:
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