The diagram and the required components of force on given block are shown below
From the above diagram, N=mg−F‌sin‌θ...(i) where, N=‌ normal force ‌ and F‌cos‌θ−fk=ma ⇒‌F‌cos‌θ−µkN=ma ...(ii) where, fk= kinetic friction force. From Eq. (i) and Eq. (ii), we get F‌cos‌θ−µk(mg−F‌sin‌θ)=ma ⇒‌‌a=‌
F
m
‌cos‌θ−µk(g−‌
F
m
‌sin‌θ) This is the required acceleration of the block.