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JEE Main 16 March 2021 Shift 2 Solved Paper
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© examsnet.com
Question : 27
Total: 90
A swimmer can swim with velocity of
12
k
m
/
h
in still water. Water flowing in a river has velocity
6
k
m
/
h
. The direction with respect to the direction of flow of river water he should swim in order to reach the point on the other bank just opposite to his starting point is ........ (in degree).
(Round off to the nearest integer)
[16 Mar 2021 Shift 2]
Your Answer:
Validate
Solution:
The situation is depicted in the following figure.
where,
V
M
R
=
velocity of
m
a
n
=
12
k
m
/
h
and
v
R
=
velocity of water flow in river
=
6
k
m
/
h
As,
v
M
R
should be along
C
D
.
⇒
v
R
−
v
M
R
sin
θ
=
0
⇒
6
−
12
sin
θ
=
0
⇒
sin
θ
=
6
12
⇒
sin
θ
=
1
2
⇒
θ
=
sin
−
1
(
1
2
)
=
sin
−
1
(
sin
30
∘
)
[
∵
sin
30
∘
=
1
2
]
⇒
θ
=
30
∘
∴
α
=
90
∘
+
θ
=
90
∘
+
30
∘
=
120
∘
⇒
α
=
120
∘
© examsnet.com
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