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JEE Main 17 March 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 60
Total: 90
The pressure exerted by a non-reactive gaseous mixture of
6.4
g
of methane and
8.8
g
of carbon dioxide in a
10
L
vessel at
27
∘
C
is ...... kPa (Round off to the nearest integer)
(Assume gases are ideal,
R
=
8.314
J
m
o
l
−
1
K
−
1
Atomic mass, C:
12.0
u
,
H
:
1.0
u
,
O
:
16.0
u
)
[17 Mar 2021 Shift 1]
Your Answer:
Validate
Solution:
Given, mass of methane
=
6.4
g
mass of
C
O
2
=
8.8
g
volume of container
=
10
L
temperature
=
27
∘
C
To find,
p
total
=
Total pressure
Moles of
C
H
4
=
Given mass
Molar mass
=
6.4
16
=
0.4
m
o
l
Moles of
C
O
2
=
8.8
44
=
0.2
m
o
l
n
total
=
0.4
+
0.2
=
0.6
m
o
l
p
total
=
n
total
R
T
V
=
0.6
×
8.314
×
300
10
=
149.652
=
150
k
P
a
© examsnet.com
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