Let $y=y(x)$ be the solution of the differential equation $\cos x(3 \sin x+\cos x+3) d y=$ $[1+y \sin x(3 \sin x+\cos x+3)] d x$ $0 \leq x \leq \frac{\pi}{2}, y(0)=0$. Then, $y(\frac{\pi}{3})$ is equal to [17 Mar 2021 Shift 2]

Correct Answer is : 2loge(2√3+1011)

$2 \log _{e}(\frac{2 \sqrt{3}+9}{6})$

$2 \log _{e}(\frac{2 \sqrt{3}+10}{11})$

$2 \log _{e}(\frac\sqrt{3}+7}{2})$

$2 \log _{e}(\frac{3 \sqrt{3}-8}{4})$

Test Index

JEE Main 17 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 63

Total: 90

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