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JEE Main 18 March 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 13
Total: 90
A particle is travelling 4 times as fast as an electron. Assuming the ratio of de-Broglie wavelength of a particle to that of electron is
2
:
1
, the mass of the particle is
[18 Mar 2021 Shift 1]
1
16
times the mass of electron
8 times the mass of electron
16 times the mass of electron
1
8
times the mass of electron
Validate
Solution:
Given,
λ
p
λ
e
=
2
1
,
v
e
v
p
=
1
4
We know that, de-Broglie wavelength,
λ
=
h
m
v
⇒
λ
p
λ
e
=
m
e
v
e
m
p
v
p
⇒
2
1
=
m
e
m
p
(
1
4
)
⇒
m
p
=
1
8
m
e
© examsnet.com
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