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JEE Main 18 March 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 49
Total: 90
In a binary compound, atoms of element
A
form a hcp structure and those of element
M
occupy
2
/
3
of the tetrahedral voids of the hcp structure. The formula of the binary compound is
[18 Mar 2021 Shift 1]
M
2
A
3
M
4
A
3
M
4
A
M
A
3
Validate
Solution:
For HCP unit cell,
Number of atom per unit cell
Z
=
6
, so
A
=
6
Also we know
If
Z
=
6
, so the number of tetrahedral voids
=
2
×
6
Now, if
2
/
3
of these voids are occupied by
M
the number of
M
=
2
3
×
2
×
6
=
8
∴
Formula
=
M
8
A
6
=
M
4
A
3
© examsnet.com
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