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JEE Main 18 March 2021 Shift 1 Solved Paper

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Question : 56

Total: 90

A reaction of 0.1 mole of benzylamine with bromomethane gave 23g of benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n×10−1, when n=........ (Round off to the nearest integer).
(Given : Atomic masses: C=12.0u,H=1.0u, N=14.0u,Br=80.0u ]

[18 Mar 2021 Shift 1]

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