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JEE Main 18 March 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 9
Total: 90
What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature
T
?
(
k
B
is Boltzmann constant)
[18 Mar 2021 Shift 1]
1
2
k
B
T
2
3
k
B
T
3
2
k
B
T
k
B
T
Validate
Solution:
We know that,
The average value of energy of an ideal gas in thermal equilibrium temperature
T
,
E
=
f
2
k
B
T
Given, degree of freedom,
f
=
1
Energy per degree of freedom,
E
=
1
2
k
B
T
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