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JEE Main 18 March 2021 Shift 2 Solved Paper
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© examsnet.com
Question : 18
Total: 90
An ideal gas in a cylinder is separated by a piston in such a way that the entropy of one part is
S
1
and that of the other part is
S
2
. Given that
S
1
>
S
2
. If the piston is removed, then the total entropy of the system will be
[18 Mar 2021 Shift 2]
S
1
×
S
2
S
1
−
S
2
S
1
S
2
S
1
+
S
2
Validate
Solution:
Entropy present in one part of the system is
S
1
.
Entropy present in other part of the system is
S
2
.
After removing piston,
We know that,
∆
S
unvi
=
∆
S
sys
+
∆
S
surr
Thus, after removing the piston, the total entropy present in system,
S
tot
=
S
1
+
S
2
© examsnet.com
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