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JEE Main 20 July 2021 Shift 2 Solved Paper
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© examsnet.com
Question : 1
Total: 90
If the Kinetic energy of a moving body becomes four times its initial Kinetic energy, then the percentage change in its momentum will be :
[20 Jul 2021 Shift 2]
100%
200%
300%
400%
Validate
Solution:
K
2
=
4
K
1
1
2
m
v
2
2
=
4
1
2
m
v
1
2
v
2
=
2
v
1
P
=
m
v
P
2
=
m
v
2
=
2
m
v
1
P
1
=
m
v
1
%
change
=
Δ
P
P
1
×
100
=
2
m
v
1
−
m
v
1
m
v
1
×
100
=
100
%
© examsnet.com
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