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JEE Main 2016 Paper
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Section:
Mathematics
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© examsnet.com
Question : 60 of 90
Marks:
+1
,
-0
A man is walking towards a vertical pillar in a straight path, at a uniform speed. At a certain point A on the path, he observes that the angle of elevation of the top of the pillar is 30°. After walking for 10 minutes from A in the same direction, at a point B, he observes that the angle of elevation of the top of the pillar is 60°. Then the time taken (in minutes) by him, from B to reach the pillar, is:
[Main 2016]
10
20
5
6
Validate
Solution:
tan
6
0
∘
=
h
x
⇒
h
=
3
x
\tan 60^{\circ} = \frac{h}{x} \Rightarrow h = \sqrt{3}x
tan
6
0
∘
=
x
h
⇒
h
=
3
x
tan
3
0
∘
=
h
x
⇒
3
h
=
x
+
y
\tan 30^{\circ} = \frac{h}{x} \Rightarrow \sqrt{3}h = x+y
tan
3
0
∘
=
x
h
⇒
3
h
=
x
+
y
3
x
=
x
+
y
3x = x+y
3
x
=
x
+
y
⇒
2
x
+
y
\Rightarrow 2x+y
⇒
2
x
+
y
Time taken from A to B is 10 min
So time taken from B to pillar is 5 min
© examsnet.com
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