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JEE Main 22 July 2021 Shift 2 Solved Paper
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© examsnet.com
Question : 19
Total: 90
An electric dipole is placed on
x
-axis in proximity to a line charge of linear charge density
3.0
×
10
−
6
C
∕
m
. Line charge is placed on z-axis and positive and negative charge of dipole is at a distance of
10
m
m
and
12
m
m
from the origin respectively. If total force of
4
N
is exerted on the dipole, find out the amount of positive or negative charge of the dipole.
[22 Jul 2021 Shift 2]
815.1
n
C
8.8
µ
C
0.485
m
C
4.44
µ
C
Validate
Solution:
r
=
10
m
m
,
x
=
2
,
|
→
F
q
|
=
2
k
λ
r
.
q
|
→
F
−
q
|
=
2
k
λ
r
+
x
.
q
⇒
|
→
F
n
e
t
|
=
2
k
λ
q
r
−
2
k
λ
q
r
+
x
|
→
F
n
e
t
|
=
2
k
λ
q
.
x
r
(
r
+
x
)
4
=
2
×
9
×
10
9
×
3
×
10
−
6
×
q
×
2
m
m
10
m
m
.12
m
m
⇒
q
=
4.44
µ
C
© examsnet.com
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