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JEE Main 24 Feb 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 21
Total: 90
The coefficient of static friction between a wooden block of mass
0.5
k
g
and a vertical rough wall is
0.2
. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be ....... N.
[Take,
g
=
10
m
s
−
2
]
24 Feb 2021 Shift1
Your Answer:
Validate
Solution:
Given, coefficient of static friction,
µ
s
=
0.2
Various forces acting on block are shown below
Frictional force
≤
m
g
⇒
N
×
0.2
≤
5
⇒
N
≤
25
∴
Magnitude of horizontal force,
F
=
N
=
25
N
© examsnet.com
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