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JEE Main 24 Feb 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 35
Total: 90
(A)
H
O
C
l
+
H
2
O
2
⟶
H
3
O
+
+
C
l
−
+
O
2
(B)
I
2
+
H
2
O
2
+
2
O
H
−
⟶
2
I
−
+
2
H
2
O
+
O
2
Choose the correct option.
[24 Feb 2021 Shift 1]
H
2
O
2
acts as oxidising agent in equations (A) and (B).
H
2
O
2
acts as reducing agent in equations (A) and (B).
H
2
O
2
act as oxidising and reducing agent respectively in equations (A) and (B).
H
2
O
2
acts as reducing and oxidising agent respectively in equations (A) and (B).
Validate
Solution:
In equation (A),
H
O
C
l
undergoes reduction in presence of
H
2
O
2
.
Here, oxidation state of
C
l
changes from
+
1
to
−
1
(i.e. reduces)
∴
H
2
O
2
act as reducing agent
I
2
reduces to
T
in presence of
H
2
O
2
.
In equation (B),
Here oxidation state of iodine decreases (from 0 to
−
1
)
∴
H
2
O
2
act as reducing agent in both the equations.
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