JEE Main 24 Feb 2021 Shift 1 Solved Paper

As, AB is isothermal process, so work done by isothermal process is given by
‌WAB=nRT‌ln(‌

V2

V1

)
‌WAB=nRT‌ln(‌

2V1

V1

)=nRT‌ln‌2
As, BC is isobaric process, so work done by isobaric process is given by
WBC‌‌=p∆V=p2(V1−V2)
‌‌=p2(‌

V2

2

−V2)=−‌

p2V2

2

‌‌=‌

−nRT

2

As, CA is isochoric process,
so work done by isochoric process is given by,
WCA=0‌‌[∵∆V=0]
Total work done in the cycle ABCA,
WABCA‌‌=WAB+WBC+WCA
‌‌=nRT‌ln‌2+(‌

−nRT

2

)+0
‌‌=nRT(ln‌2−‌

1

2

)