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Test Index
JEE Main 24 Jan 2025 Shift 1 Paper
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Section:
Chemistry
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© examsnet.com
Question : 55 of 75
Marks:
+1
,
-0
Which of the following statement is true with respect to
H
2
O
,
N
H
3
\mathrm{H}_2\mathrm{O}, \mathrm{NH}_3
H
2
O
,
NH
3
and
C
H
4
\mathrm{CH}_4
CH
4
?
A. The central atoms of all the molecules are
s
p
3
\mathrm{sp}^3
sp
3
hybridized.
B. The
H
−
O
−
H
,
H
−
N
−
H
\mathrm{H}-\mathrm{O}-\mathrm{H}, \mathrm{H}-\mathrm{N}-\mathrm{H}
H
−
O
−
H
,
H
−
N
−
H
and
H
−
C
−
H
\mathrm{H}-\mathrm{C}-\mathrm{H}
H
−
C
−
H
angles in the above molecules are
104.
5
∘
,
107.
5
∘
104.5^{\circ}, 107.5^{\circ}
104.
5
∘
,
107.
5
∘
and
109.
5
∘
109.5^{\circ}
109.
5
∘
, respectively.
C. The increasing order of dipole moment is
C
H
4
\mathrm{CH}_4
CH
4
<
N
H
3
<
H
2
O
< \mathrm{NH}_3< \mathrm{H}_2\mathrm{O}
<
NH
3
<
H
2
O
.
D. Both
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
and
N
H
3
\mathrm{NH}_3
NH
3
are Lewis acids and
C
H
4
\mathrm{CH}_4
CH
4
is a Lewis base.
E. A solution of
N
H
3
\mathrm{NH}_3
NH
3
in
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
is basic. In this solution
N
H
3
\mathrm{NH}_3
NH
3
and
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
act as Lowry-Bronsted acid and base respectively Choose the correct answer from the options given below
[24 Jan 2025 Shift 1]
A, B and C only
A, B, C and E only
C, D and E only
A, D and E only
Validate
Solution:
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
N
H
3
\mathrm{NH}_3
NH
3
C
H
4
\mathrm{CH}_4
CH
4
Hybridization
s
p
3
\mathrm{sp}^3
sp
3
s
p
3
\mathrm{sp}^3
sp
3
s
p
3
\mathrm{sp}^3
sp
3
Bond angle
104.
5
∘
104.5^{\circ}
104.
5
∘
107.
5
∘
107.5^{\circ}
107.
5
∘
109.
5
∘
109.5^{\circ}
109.
5
∘
Dipole moment
1.85
1.47
0
Both
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
&
N
H
3
\mathrm{NH}_3
NH
3
are Lewis bases.
N
H
3
\mathrm{NH}_3
NH
3
acts as base in
H
2
O
,
N
H
3
\mathrm{H}_2\mathrm{O}, \mathrm{NH}_3
H
2
O
,
NH
3
&
H
2
O
\mathrm{H}_2\mathrm{O}
H
2
O
act as Lowry - Bronsted base & acid respectively.
A, B & C are correct
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