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JEE Main 25 Feb 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 2
Total: 90
A student is performing the experiment of resonance column. The diameter of the column tube is
6
c
m
. The frequency of the tuning fork is
504
H
z
. Speed of the sound at the given temperature is
336
m
∕
s
. The zero of the meter scale coincides with the top end of the resonance column tube. The reading of the water level in the column when the first resonance occurs is
[25 Feb 2021 Shift 1]
13
c
m
16.6
c
m
8.4
c
m
14.8
c
m
Validate
Solution:
Given, diameter of the column tube,
d
=
6
c
m
=
6
×
10
−
2
m
Frequency of tuning fork,
f
=
504
H
z
Speed of sound at given temperature,
v
=
336
m
s
−
1
As, this is a closed organ pipe.
Let
L
be the length of tube and
λ
be the wavelength, then
and
L
+
e
=
λ
∕
4
=
v
∕
4
f
(
∵
λ
=
v
f
)
e
=
0.6
×
d
∕
2
=
6
10
×
6
×
10
−
2
2
=
0.018
⇒
L
+
e
=
v
4
f
=
336
4
×
504
⇒
L
=
336
2016
−
0.018
=
0.1667
−
0.018
=
0.1487
m
=
14.87
c
m
∼
e
q
14.8
c
m
© examsnet.com
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