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JEE Main 25 July 2021 Shift 2 Solved Paper
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© examsnet.com
Question : 15
Total: 90
The given potentiometer has its wire of resistance 10Ω. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2Ω resistor is :
[25 Jul 2021 Shift 2]
10
V
5
V
40
9
V
40
11
V
Validate
Solution:
20
−
V
0
5
+
0
−
V
0
5
+
20
−
V
0
2
=
0
4
+
10
=
2
V
0
5
+
V
0
2
14
=
4
V
0
+
5
V
0
10
V
0
=
140
9
V
o
l
t
Potential difference across
2
Ω
resistor is
20
−
V
0
That is
(
20
−
140
9
)
Volt
Hence answer is
(
40
9
)
Volt
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