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JEE Main 26 Feb 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 18
Total: 90
LED is constructed from GaAsP semiconducting material. The energy gap of this LED is
1.9
e
V
. Calculate the wavelength of light emitted and its colour.
[
h
=
6.63
×
10
−
34
J
s
and
c
=
3
×
10
8
m
s
−
1
]
[26 Feb 2021 Shift 1]
1046
n
m
and red colour
654
n
m
and orange colour
1046
n
m
and blue colour
654
n
m
and red colour
Validate
Solution:
Given, energy gap of LED,
E
=
1.9
e
V
Speed of light in free space,
C
=
3
×
10
8
m
s
−
1
Planck's constant,
h
=
6.63
×
10
−
34
J
−
s
As we know that,
E
=
h
c
λ
⇒
λ
=
h
c
E
⇒
λ
=
6.63
×
10
−
34
×
3
×
10
8
19
×
1.6
×
10
−
19
=
654
×
10
−
9
m
=
654
n
m
As, wavelength of red light is
600
n
m
.
∴
Required wavelength will be of red colour.
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