Given, forward resistance, R1=50Ω Reverse resistance, R2= infinity Battery voltage =6V According to circuit diagram,
In this case, diode D1 is forward biased, whereas diode D2 is reverse biased. So, D2 will act as open circuit. By using Kirchhoff's voltage law, ⇒6−50I−130I−120I=0 ⇒6=300I ⇒I=