According to given data; Initial speed of scooter, u1=0ms−1 and final speed, v2=0ms−1 By using first equation of motion, ‌v1‌‌=u+a1t1 ‌⇒‌v1‌‌=a1t1. . . (i) and for second case, v2‌‌=v1−a2t2 0‌‌=v1−a2t2 v1‌‌=a2t2 . . . (ii) On dividing Eq. (i) by Eq. (ii), we get ‌v1∕v1‌‌=1=‌