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JEE Main 27 July 2021 Shift 1 Solved Paper
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© examsnet.com
Question : 16
Total: 90
A ball is thrown up with a certain velocity so that it reaches a height '
h
'. Find the ratio of the two different times of the ball reaching
h
3
in both the directions.
[27 Jul 2021 Shift 1]
√
2
−
1
√
2
+
1
1
3
√
3
−
√
2
√
3
+
√
2
√
3
−
1
√
3
+
1
Validate
Solution:
u
=
√
2
g
h
Now,
S
=
h
3
a
=
−
g
S
=
u
t
+
1
2
a
t
2
h
3
=
√
2
g
h
t
+
1
2
(
−
g
)
t
2
t
2
(
g
2
)
−
√
2
g
h
t
+
h
3
=
0
From quadratic equation
t
1
,
t
2
=
√
2
g
h
±
√
2
g
h
−
4
g
2
h
3
g
t
1
t
2
=
√
2
g
h
−
√
4
g
h
3
√
2
g
h
+
√
4
g
h
3
=
√
3
−
√
2
√
3
+
√
2
© examsnet.com
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