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JEE Main 27 July 2021 Shift 1 Solved Paper

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Question : 19

Total: 90

Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.
Reason R :
Least Count =

Total divisionson circular scale

In the light of the above statements, choose the most appropriate answer from the options given below :

[27 Jul 2021 Shift 1]

A is not correct but R is correct.
Both A and R are correct and R is the correct explanation of A.
A is correct but R is not correct.
Both A and R are correct and R is NOT the correct explanation of A.

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