Exams Net
Unrestricted Exams Practice
Home
Exams
Banking
CUET
Defence
Engineering
Finance
GATE
Insurance
International
JEE
LAW
MBA
MCA
Medical
Other
Police
PSC
RRB
SSC
State Govt
Subjectwise
Teacher
SET Exams
UPSC
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
CBSE
CBSE Class 10 Solutions
CBSE Class 12 Solutions
CBSE Question Papers (Pdf)
NCERT Books (Pdf)
NCERT Exemplar Books (Pdf)
NCERT Study Notes (Pdf)
CBSE Study Concepts (Pdf)
NCERT Text Book Class 11 Solutions
NCERT Text Book Class 12 Solutions
ICSE Class 10 Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
JEE Main 29 Jan 2025 Shift 1 Paper
Show Para
Hide Para
Section:
Physics
Share question:
© examsnet.com
Question : 41 of 75
Marks:
+1
,
-0
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion
(A) : Emission of electrons in photoelectric effect can be suppressed by applying a sufficiently negative electron potential to the photoemissive substance.
Reason
(R) : A negative electric potential, which stops the emission of electrons from the surface of a photoemissive substance, varies linearly with frequency of incident radiation.
In the light of the above statements, choose the most appropriate answer from the options given below:
[29 Jan 2025 Shift 1]
(A) is true but (R) is false
Both (A) and (R) are true and (R) is the correct explanation of (A)
(A) is false but (R) is true
Both (A) and (R) are true but (R) is not the correct explanation of (A)
Validate
Solution:
👈: Video Solution
Negative potential will slow the electrons and if it is sufficient, it will make the photocurrent zero.
e
V
 
s
=
h
f
−
Ï•
0
\mathrm{eV}\,\mathrm{s} = h f - \phi_0
eV
s
=
h
f
−
Ï•
0
​
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
Prev Question
Next Question
More Free Exams
AIEEE Previous Papers
BITSAT Exam Previous Papers
JEE Adv
JEE Advanced Model Papers
JEE Advanced Previous Papers
JEE Main
JEE Mains Model Papers
VITEEE Previous Papers