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Test Index
JEE Main 3 Apr 2025 Shift 1 Paper
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Section:
Physics
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© examsnet.com
Question : 28 of 75
Marks:
+1
,
-0
Consider following statements for refraction of light through prism, when angle of deviation is minimum.
A. The refracted ray inside prism becomes parallel to the base.
B. Larger angle prisms provide smaller angle of minimum deviation.
C. Angle of incidence and angle of emergence becomes equal.
D. There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.
E. Angle of refraction becomes double of prism angle.
Choose the correct answer from the options given below:
[3 Apr 2025 Shift 1]
A, B and E only
B, D and E only
B, C and D only
A, C and D only
Validate
Solution:
Because of symmetry where
i
=
r
i=r
i
=
r
, and
r
=
  
A
2
r=\;\frac{A}{2}
r
=
2
A
​
δ
=
(
μ
−
1
)
A
\delta=(\mu-1) A
δ
=
(
μ
−
1
)
A
(A) is correct
(B) is incorrect
(C) is correct
(D) is correct as
δ
=
i
+
e
−
A
\delta=i+e-A
δ
=
i
+
e
−
A
(E) is incorrect
© examsnet.com
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