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JEE Main 7 Jan 2020 Shift 1 Solved Paper
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© examsnet.com
Question : 23
Total: 75
A beam of electromagnetic radiation of intensity
6.4
×
10
–
5
W/cm
2
is comprised of wavelength,
λ
=
310
n
m
. It falls normally on a metal (work function φ = 2eV) of surface area of 1
c
m
2
. If one in
10
3
photons ejects an electron, total number of electrons ejected in 1 s is
10
x
. (hc=1240 eVnm, 1eV =
1.6
×
10
–
19
J), then x is____ .
[7-Jan-2020 Shift 1]
Your Answer:
Validate
Solution:
Power incident P = I × A
n = no. of photons incident/second
n
E
p
h
=
I
A
n
=
I
A
E
p
h
n
=
I
A
(
h
c
λ
)
=
6.4
×
10
−
5
×
1
1240
310
×
1.6
×
10
−
19
n
=
10
+
14
per second
Since efficiency =
10
–
3
no. of electrons emitted =
10
+
11
per second.
x = 11.
© examsnet.com
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