Test Index

JEE Main 7 Jan 2020 Shift 2 Solved Paper

© examsnet.com

Question : 13

Total: 75

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45° with the vertical. Then F equals: (Take g = 10 ms‌–2 and the rope to be massless)

100 N
90 N
75 N
70 N

Go to Question:

Prev Question

Next Question