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JEE Main 8 Apr 2019 Paper 1 Solved Paper

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Question : 2

Total: 91

Two particles move at right angle to each other. Their de Broglie wavelengths are λ1 and λ2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength λ , of the final particle, is given by:

λ=√λ1λ2
λ=
λ1+λ2
2
2
λ
=
1
λ1
+
1
λ2
1
λ2
=
1
λ12
+
1
λ22

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