The bob of a simple pendulum has mass 2 g and a charge of 5.0\mu C. It is at rest in a uniform horizontal electric field of intensity 2000 V/ m. At equilibrium, the angle that the pendulum makes with the vertical is (take g = 10 m/s^2 )
[8 Apr 2019 Shift 1]

Question

Examsnet · Accepted Answer

Correct Answer is : tan−1(0.5)

JEE Main 8 Apr 2019 Paper 1 Solved Paper