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JEE Main 8 Apr 2019 Paper 1 Solved Paper
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© examsnet.com
Question : 69
Total: 91
The shortest distance between the line
y
=
x
and the curve
y
2
=
x
−
2
is
11
4
√
2
7
8
2
7
4
√
2
Validate
Solution:
Eq. of tangent to
y
2
=
x
−
2
,
which is parallel to
y
=
x
is
y
=
x
−
2
+
1
4
⇒
y
=
x
−
7
4
∴
S
.
D
=
7
4
√
2
© examsnet.com
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