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JEE Main 8 Apr 2019 Paper 2 Solved Paper
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© examsnet.com
Question : 13
Total: 90
A body of mass m1 moving with an unknown velocity of
v
1
^
i
, undergoes a collinear collision with a body of mass
m
2
moving with a velocity
v
2
^
i
. After collision,
m
1
and
m
2
move with velocities of
v
3
^
i
and
v
4
^
i
, respectively. If
m
2
=
0.5
m
1
and
v
3
=
0.5
v
1
, then
v
1
is:
v
4
−
v
2
2
v
4
+
v
2
v
4
−
v
2
4
v
4
−
v
2
Validate
Solution:
m
1
→
v
1
+
m
2
→
v
2
=
m
1
→
v
3
+
m
2
→
v
4
2
m
2
=
m
1
and Let
m
2
=
m
2
m
v
1
+
m
v
2
=
2
m
(
0.5
v
1
)
+
m
v
4
⇒
v
1
=
v
4
−
v
2
© examsnet.com
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