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JEE Main 8 Apr 2019 Paper 2 Solved Paper
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© examsnet.com
Question : 18
Total: 90
Let
|
→
A
1
|
=
3
,
|
→
A
2
|
=
5
and
|
→
A
1
+
→
A
2
|
=
5
.
The value of
(
2
→
A
1
+
3
→
A
2
)
.
(
3
→
A
1
−
2
→
A
2
)
is:
–106.5
–112.5
–99.5
–118.5
Validate
Solution:
(
→
A
1
+
→
A
2
)
.
(
→
A
1
+
→
A
2
)
=
25
⇒
9
+
25
+
2
(
→
A
1
.
→
A
2
)
=
25
⇒
→
A
1
.
→
A
2
=
−
9
2
=
6
A
1
2
−
6
A
2
2
+
5
→
A
1
.
→
A
2
⇒
6
×
9
−
6
×
25
+
5
×
−
9
2
=
–
69
+
(
–
22.5
)
=
–
118.5
© examsnet.com
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