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JEE Main 8 Jan 2020 Shift 2 Solved Paper
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© examsnet.com
Question : 2
Total: 75
In a double slit experiment, at a certain point on the screen the path difference between the two interfering waves is
1
8
th of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is :
0.568
0.672
0.760
0.853
Validate
Solution:
I
=
I
0
cos
2
(
Δ
ϕ
2
)
I
I
0
=
cos
2
(
Δ
ϕ
2
)
I
I
0
=
cos
2
(
2
π
λ
×
λ
8
2
)
I
I
0
=
cos
2
(
π
8
)
I
I
0
=
0.853
© examsnet.com
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